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8x=x^2/3
We move all terms to the left:
8x-(x^2/3)=0
We get rid of parentheses
-x^2/3+8x=0
We multiply all the terms by the denominator
-x^2+8x*3=0
We add all the numbers together, and all the variables
-1x^2+8x*3=0
Wy multiply elements
-1x^2+24x=0
a = -1; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-1)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-1}=\frac{-48}{-2} =+24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-1}=\frac{0}{-2} =0 $
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